document.write( "Question 1060304: The sum of the ages of sam and thomas is 27 years. Seven years ago, thomas was three years more than one-fourth as old as sam.find their present ages.
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Algebra.Com's Answer #675294 by Fombitz(32388) $\"\"$ $\"About$

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$\"S%2BT=27\"$
\n" ); document.write( "Seven years ago,
\n" ); document.write( " $\"T-7=3%2B%28S-7%29%2F4\"$
\n" ); document.write( " $\"4%28T-7%29=12%2BS-7\"$
\n" ); document.write( " $\"4T-28=5%2BS\"$
\n" ); document.write( " $\"4T=S%2B33\"$
\n" ); document.write( "From eq. 1,
\n" ); document.write( " $\"T=27-S\"$
\n" ); document.write( "Substituting,
\n" ); document.write( " $\"4%2827-S%29=S%2B33\"$
\n" ); document.write( " $\"108-4S=S%2B33\"$
\n" ); document.write( " $\"-5S=-75\"$
\n" ); document.write( " $\"S=15\"$
\n" ); document.write( "So then,
\n" ); document.write( " $\"15%2BT=27\"$
\n" ); document.write( " $\"T=12\"$
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