document.write( "Question 92788: If x, y, and z are positive intergers such that the value of x+y is even and the value of +x+z is odd, which of the following must be true?\r
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document.write( "(A) x is odd
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document.write( "(B) x is even
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document.write( "(C) If z is even, then x is odd
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document.write( "(D) If z is even, then xy is even
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document.write( "(E) xy is even \n" );
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Algebra.Com's Answer #67529 by Edwin McCravy(20060) You can put this solution on YOUR website! \r\n" ); document.write( "If x, y, and z are positive integers such that the value of x+y\r\n" ); document.write( "is even and the value of (x+y)²+x+z is odd, which of the following\r\n" ); document.write( "must be true?\r\n" ); document.write( "\r\n" ); document.write( "(A) x is odd\r\n" ); document.write( "(B) x is even\r\n" ); document.write( "(C) If z is even, then x is odd\r\n" ); document.write( "(D) If z is even, then xy is even\r\n" ); document.write( "(E) xy is even\r\n" ); document.write( "\r\n" ); document.write( "There are 8 possible cases:\r\n" ); document.write( "We can use any even and odd integer. The easiest even positive\r\n" ); document.write( "integer is 2 and the easiest odd integer is 1. So let's use\r\n" ); document.write( "these in those 8 cases\r\n" ); document.write( "\r\n" ); document.write( " x y z x+z=? (x+y)²+x+z=?\r\n" ); document.write( "------------------------------------------------------------ \r\n" ); document.write( "1. 2 2 2 2+2=4=EVEN (2+2)²+2+2=4²+2+2=16+2+2=20=EVEN \r\n" ); document.write( "2. 2 2 1 2+1=3=ODD (2+2)²+2+1=4²+2+1=16+2+1=19=ODD \r\n" ); document.write( "3. 2 1 2 2+2=4=EVEN (2+1)²+2+2=3²+2+2= 9+2+2=13=EVEN\r\n" ); document.write( "4. 2 1 1 2+1=3=ODD (2+1)²+2+1=3²+2+1= 9+2+1=12=EVEN\r\n" ); document.write( "5. 1 2 2 1+2=3=ODD (1+2)²+1+2=3²+1+2= 9+1+2=12=EVEN \r\n" ); document.write( "6. 1 2 1 1+2=3=ODD (1+2)²+1+1=3²+1+1= 9+1+1=11=ODD\r\n" ); document.write( "7. 1 1 2 1+1=2=EVEN (1+1)²+1+2=2²+1+2= 4+1+2= 7=ODD\r\n" ); document.write( "8. 1 1 1 1+1=2=EVEN (1+1)²+1+1=2²+1+1= 4+1+1= 6=EVEN\r\n" ); document.write( "\r\n" ); document.write( "There are only one case when x+y is EVEN and (x+y)²+x+z is ODD,\r\n" ); document.write( "That is case 7, where x=1, y=1 and z=2\r\n" ); document.write( "\r\n" ); document.write( "So x is odd, y is odd, and z is even. \r\n" ); document.write( " \r\n" ); document.write( "The only one of the choices that must be true is A.\r\n" ); document.write( "\r\n" ); document.write( "Edwin \n" ); document.write( " \n" ); document.write( " |