document.write( "Question 1060305: The sum of the squares of two consecutive positive odd integers is 103 more than the product of these two integers.Find the integers \n" ); document.write( "

Algebra.Com's Answer #675287 by stanbon(75887) $\"\"$ $\"About$

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The sum of the squares of two consecutive positive odd integers is 103 more than the product of these two integers.Find the integers
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\n" ); document.write( "1st odd:: 2x-1
\n" ); document.write( "2nd odd:: 2x++1
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\n" ); document.write( "Equation:
\n" ); document.write( "(2x-1)^2 + (2x+1)^2 = (2x-1)(2x+1)+103
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\n" ); document.write( "4x^2 - 4x +1 + 4x^2 + 4x + 1 = 4x^2-1+103
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\n" ); document.write( "8x^2 +2 = 4x^2+102
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\n" ); document.write( "4x^2 = 100
\n" ); document.write( "x^2 = 25
\n" ); document.write( "x = 5 or x = -5
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\n" ); document.write( "1st solution:: 2x-1 = 2*5-1 = 9 and 2x+1 = 11
\n" ); document.write( "2nd solution:: 2x-1 = 2*-5-1 = -11 and 2x+1 = 2(-5)+1 = -9
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\n" ); document.write( "Cheers,
\n" ); document.write( "Stan H.
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