document.write( "Question 1060305: The sum of the squares of two consecutive positive odd integers is 103 more than the product of these two integers.Find the integers \n" ); document.write( "
Algebra.Com's Answer #675286 by rothauserc(4718)\"\" \"About 
You can put this solution on YOUR website!
let x and x+2 be the two odd integers
\n" ); document.write( ":
\n" ); document.write( "x^2 + (x+2)^2 = x * (x+2) + 103
\n" ); document.write( ":
\n" ); document.write( "x^2 +x^2+4x+4 = x^2 +2x +103:
\n" ); document.write( ":
\n" ); document.write( "x^2 +2x -99 = 0
\n" ); document.write( ":
\n" ); document.write( "(x+11) * (x-9) = 0
\n" ); document.write( ":
\n" ); document.write( "x = -11 or x = 9
\n" ); document.write( ":
\n" ); document.write( "*************************
\n" ); document.write( "There are two solutions
\n" ); document.write( ":
\n" ); document.write( "9 and 11
\n" ); document.write( ":
\n" ); document.write( "-11 and -9
\n" ); document.write( ":
\n" ); document.write( "*************************
\n" ); document.write( ":
\n" ); document.write( "
\n" ); document.write( "
\n" );