document.write( "Question 1060305: The sum of the squares of two consecutive positive odd integers is 103 more than the product of these two integers.Find the integers \n" ); document.write( "
Algebra.Com's Answer #675286 by rothauserc(4718) You can put this solution on YOUR website! let x and x+2 be the two odd integers \n" ); document.write( ": \n" ); document.write( "x^2 + (x+2)^2 = x * (x+2) + 103 \n" ); document.write( ": \n" ); document.write( "x^2 +x^2+4x+4 = x^2 +2x +103: \n" ); document.write( ": \n" ); document.write( "x^2 +2x -99 = 0 \n" ); document.write( ": \n" ); document.write( "(x+11) * (x-9) = 0 \n" ); document.write( ": \n" ); document.write( "x = -11 or x = 9 \n" ); document.write( ": \n" ); document.write( "************************* \n" ); document.write( "There are two solutions \n" ); document.write( ": \n" ); document.write( "9 and 11 \n" ); document.write( ": \n" ); document.write( "-11 and -9 \n" ); document.write( ": \n" ); document.write( "************************* \n" ); document.write( ": \n" ); document.write( " \n" ); document.write( " |