document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1060315>Question 1060315</A>: <I><SPAN STYLE=\"word-break: break-all;\"> A football field has a perimeter of 310 yd and an area of 4950 yd square. What are the dimensions of the field? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #675277 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=675277\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> A football field has a perimeter of 310 yd and an area of 4950 yd square. What are the dimensions of the field? <BR>\n" );
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document.write( "2(L+W) = 310<BR>\n" );
document.write( "L*W = 4950<BR>\n" );
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document.write( "L = 155-W<BR>\n" );
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document.write( "(155-W)W = 4950<BR>\n" );
document.write( "-W^2 + 155W - 4950  = 0<BR>\n" );
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document.write( "W^2 - 155W + 4950 = 0<BR>\n" );
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document.write( "(W-110)(W-45) = 0<BR>\n" );
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document.write( "Usable solution:: <BR>\n" );
document.write( "Width = 110 yrd<BR>\n" );
document.write( "Length = 155-W = 45 yrd<BR>\n" );
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document.write( "Cheers,<BR>\n" );
document.write( "Stan H.<BR>\n" );
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document.write( " </SPAN>\n" );
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