document.write( "Question 1060297: Find the exact value of the trigonometric function given that sin u = 5/13 and cos v = -3/5 (Both are in Quadrant II.) sec (v - u) \n" ); document.write( "
Algebra.Com's Answer #675256 by Edwin McCravy(20060)\"\" \"About 
You can put this solution on YOUR website!
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document.write( "\"sec%28v+-+u%29\"\"%22%22=%22%22\"\"1%2Fcos%28v-u%29\"\"%22%22=%22%22\"\"1%2F%28cos%28v%29cos%28u%29%2Bsin%28v%29sin%28u%29%29\"\"%22%22=%22%22\"\"1%5B%22%22%5D%2F%28%28-3%2F5%29cos%28u%29%2Bsin%28v%29%285%2F13%29%29\"\"%22%22=%22%22\"\r\n" );
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document.write( "We have to pause here and use an identity:\r\n" );
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document.write( "\"sin%5E2%28theta%29%2Bcos%5E2%28theta%29\"\"%22%22=%22%22\"\"1\"\r\n" );
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document.write( "we use it to find cos(u) from sin(u):\r\n" );
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document.write( "\"sin%5E2%28u%29%2Bcos%5E2%28u%29\"\"%22%22=%22%22\"\"1\"\r\n" );
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document.write( "\"%285%2F13%29%5E2%2Bcos%5E2%28u%29\"\"%22%22=%22%22\"\"1\"\r\n" );
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document.write( "\"25%2F169%2Bcos%5E2%28u%29\"\"%22%22=%22%22\"\"1\"\r\n" );
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document.write( "Multiply through by 169\r\n" );
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document.write( "\"25%2B169cos%5E2%28u%29\"\"%22%22=%22%22\"\"169\"\r\n" );
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document.write( "Subtract 25 from both sides:\r\n" );
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document.write( "\"169cos%5E2%28u%29\"\"%22%22=%22%22\"\"144\"\r\n" );
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document.write( "\"cos%5E2%28u%29\"\"%22%22=%22%22\"\"144%2F169\"\r\n" );
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document.write( "\"cos%28u%29\"\"%22%22=%22%22\"\"%22%22+%2B-+sqrt%28144%2F169%29\"\r\n" );
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document.write( "\"cos%28u%29\"\"%22%22=%22%22\"\"%22%22+%2B-+12%2F13\"\r\n" );
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document.write( "We can determine which sign + or - to use because\r\n" );
document.write( "we know that both are in Quadrant II, and the\r\n" );
document.write( "cosine is negative in quadrant II.  So \"cos%28u%29\"\"%22%22=%22%22\"\"-12%2F13\"\r\n" );
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document.write( "we can now substitute that in \r\n" );
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document.write( "\"1%5B%22%22%5D%2F%28%28-3%2F5%29cos%28u%29%2Bsin%28v%29%285%2F13%29%29\"\"%22%22=%22%22\"\r\n" );
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document.write( "\"1%5B%22%22%5D%2F%28%28-3%2F5%29%28-12%2F13%29%2Bsin%28v%29%285%2F13%29%29\"\"%22%22=%22%22\"\r\n" );
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document.write( "But we still need sin(v).  So we go back to the identity:\r\n" );
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document.write( "\"sin%5E2%28theta%29%2Bcos%5E2%28theta%29\"\"%22%22=%22%22\"\"1\"\r\n" );
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document.write( "we use it to find sin(v) from cos(v):\r\n" );
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document.write( "\"sin%5E2%28v%29%2Bcos%5E2%28v%29\"\"%22%22=%22%22\"\"1\"\r\n" );
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document.write( "\"sin%5E2%28v%29%2B%28-3%2F5%29%5E2\"\"%22%22=%22%22\"\"1\"  \r\n" );
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document.write( "\"sin%5E2%28v%29%2B9%2F25\"\"%22%22=%22%22\"\"1\"\r\n" );
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document.write( "Multiply through by 25\r\n" );
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document.write( "\"25sin%5E2%28v%29%2B9\"\"%22%22=%22%22\"\"25\"\r\n" );
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document.write( "Subtract 9 from both sides:\r\n" );
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document.write( "\"25sin%5E2%28v%29\"\"%22%22=%22%22\"\"16\"\r\n" );
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document.write( "\"sin%5E2%28v%29\"\"%22%22=%22%22\"\"16%2F25\"\r\n" );
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document.write( "\"sin%28v%29\"\"%22%22=%22%22\"\"%22%22+%2B-+sqrt%2816%2F25%29\"\r\n" );
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document.write( "\"sin%28v%29\"\"%22%22=%22%22\"\"%22%22+%2B-+4%2F5\"\r\n" );
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document.write( "As before we can determine which sign + or - to use because\r\n" );
document.write( "we know that both are in Quadrant II, and the sine is\r\n" );
document.write( "positive in quadrant II.  So \"sin%28v%29\"\"%22%22=%22%22\"\"%22%22+%2B+4%2F5\"\r\n" );
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document.write( "we can now substitute that in \r\n" );
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document.write( "\"1%5B%22%22%5D%2F%28%28-3%2F5%29%28-12%2F13%29%2B%284%2F5%29%285%2F13%29%29\"\"%22%22=%22%22\"\"1%5B%22%22%5D%2F%28%2836%2F65%29%2B%2820%2F65%29%29\"\"%22%22=%22%22\"\"%281%5B%22%22%5D%29%2F%2856%2F65%29\"\"%22%22=%22%22\"\"1\"\"%22%F7%22\"\"56%2F65\"\"%22%22=%22%22\"\"1\"\"%22%22%2A%22%22\"\"65%2F56\"\"%22%22=%22%22\"\"65%2F56\"\r\n" );
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document.write( "Answer: \"65%2F56\"\r\n" );
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document.write( "Edwin
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