document.write( "Question 1060240: I drove to my parents' house at 60 miles per hour. If I had driven 50 miles an hour instead, then I would have gotten there 40 minutes later. How many miles did I drive? \n" ); document.write( "
Algebra.Com's Answer #675233 by ikleyn(52775)\"\" \"About 
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\n" ); document.write( "I drove to my parents' house at 60 miles per hour. If I had driven 50 miles an hour instead,
\n" ); document.write( "then I would have gotten there 40 minutes later. How many miles did I drive?
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document.write( "Let D be the distance under the question.\r\n" );
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document.write( "When you drove to parents at 60 mph, you spent \"D%2F60\" hours.\r\n" );
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document.write( "When you drove back at 50 mph, you spent \"D%2F50\" hours.\r\n" );
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document.write( "The difference was 40 minutes, or \"2%2F3\" of an hour.\r\n" );
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document.write( "It gives you an equation\r\n" );
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document.write( "\"D%2F50+-+D%2F60\" = \"2%2F3\".\r\n" );
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document.write( "To solve it, multiply both sides by 300. You will get\r\n" );
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document.write( "6D - 5D = 200,  or\r\n" );
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document.write( "D = 200.\r\n" );
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document.write( "Answer.  The distance was 200 miles.\r\n" );
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document.write( "Check.   \"200%2F50\" = 4 hours.  \"200%2F60\" = \"3\" \"1%2F3\" hours.  4 hours - \"3\" \"1%2F3\" hour = \"2%2F3\" hour.  Correct !\r\n" );
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