document.write( "Question 13203: finding two consecutive even integers such that the smaller added to three times the larger gives a sum of 54 \n" ); document.write( "

Algebra.Com's Answer #6752 by akmb1215(68) $\"\"$ $\"About$

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Two consecutive even integers, as variables, can be written as n and n+2 (it is n+2 because the next even integer is 2 more than the previous one - like 2 and 4.). So, your equation for this problem will be $\"n+%2B+3%28n+%2B+2%29+=+54\"$ . Start solving by using the distributive property to get $\"n+%2B+3n+%2B+6+=+54\"$ . Combine like terms to get $\"4n+%2B+6+=+54\"$ . Move the 6 to the other side of the equal sign to get $\"4n+=+48\"$ . Divide to solve for n, and you get $\"n+=+12\"$ . The answer to your question is 12 and 14. \n" ); document.write( "

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