document.write( "Question 1060161: The measure of the first angle of a triangle is 16 º less than the measure of the second angle. The measure of the third angle is double the measure of the second angle.\r
\n" ); document.write( "\n" ); document.write( "Write an algebraic equation to find the measure of each angle and solve the equation for x\r
\n" ); document.write( "\n" ); document.write( "Calculate the measure of each angle and check by showing that the sum of the angles = 180º \n" ); document.write( "

Algebra.Com's Answer #675170 by jorel555(1290) $\"\"$ $\"About$

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Let the second angle be n. Then the first angle is n-16, and the third angle is 2n. So:
\n" ); document.write( "n+n-16+2n=180
\n" ); document.write( "4n=196
\n" ); document.write( "n=49
\n" ); document.write( "The first angle is 33°, the second angle is 49°, and the third angle is 98°. ☺☺☺☺ \n" ); document.write( "

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