document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=92780>Question 92780</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Use the Pythagorean theorem to determine the length of each line segment. Round to the nearest hundredth where appropriate.<BR>\n" );
document.write( "(1,-1)and (3,2) </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #67517 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=67517\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Use the Pythagorean theorem to determine the length of each line segment. Round to the nearest hundredth where appropriate.<BR>\n" );
document.write( "(1,-1)and (3,2)<BR>\n" );
document.write( "-----------<BR>\n" );
document.write( "distance = sqrt[(2--1)^2 + (3-1)^2]<BR>\n" );
document.write( "distance = sqrt[ 9 + 4]<BR>\n" );
document.write( "distance = sqrt(13) = 3.6055....<BR>\n" );
document.write( "Cheers,<BR>\n" );
document.write( "Stan H. </SPAN>\n" );
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