document.write( "Question 92755This question is from textbook
\n" ); document.write( ": 1. (Age) a father is now three times as old as his son. Twelve years ago he was six times as old as his son. Find the present age of each. \n" ); document.write( "

Algebra.Com's Answer #67511 by Edwin McCravy(20056) $\"\"$ $\"About$

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1. (Age) a father is now three times as old as his son.
\n" ); document.write( "Twelve years ago he was six times as old as his son.
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document.write( "Let son's present age = x.\r\n" );
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\n" ); document.write( ">>...father is now three times as old as his son...<<
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document.write( "So father's present age = 3x\r\n" );
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\n" ); document.write( ">>...Twelve years ago...<<
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document.write( "Son's age twelve years ago = x-12\r\n" );
document.write( "Father's age twelve years ago = 3x-12 \r\n" );
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\n" ); document.write( ">>...Twelve years ago he (father) was six times as old as his son...<<
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document.write( "(Father's age 12 years ago) = 6 times (son's age 12 years ago)\r\n" );
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document.write( "or\r\n" );
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document.write( "                      3x-12 = 6(x-12)\r\n" );
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document.write( "Solve that and get x = 20\r\n" );
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document.write( "So the son's present age is x, or 20, and the father's present age\r\n" );
document.write( "is 3x or 3(20) = 60.\r\n" );
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document.write( "Checking: 12 years ago, the son was 20-12 or 8, and the father was \r\n" );
document.write( "60-12 or 48, and 48 is indeed 6 times 8.\r\n" );
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document.write( "Edwin

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