document.write( "Question 1060100: Find the natural domain of y=1/sqr(-(2-x))\r
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Algebra.Com's Answer #675107 by ikleyn(52833)![]() ![]() You can put this solution on YOUR website! . \n" ); document.write( "Find the natural domain of y=1/sqr(-(2-x))\r \n" ); document.write( "\n" ); document.write( "Thanks! \n" ); document.write( "~~~~~~~~~~~~~~\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \r\n" ); document.write( "The natural domain is the set of solutions of this inequality\r\n" ); document.write( "\r\n" ); document.write( "-(2-x) >= 0, (1)\r\n" ); document.write( "\r\n" ); document.write( "making an expression under the square root positive (non-negative, to be precise).\r\n" ); document.write( "\r\n" ); document.write( "The inequality (1) is equivalent to \r\n" ); document.write( "\r\n" ); document.write( "2-x <= 0 ( ! notice I changed signs in both sides, and changed the inequality sign to the opposite ! )\r\n" ); document.write( "\r\n" ); document.write( "2 <= x, or, which is the same, \r\n" ); document.write( "\r\n" ); document.write( "x > = 2.\r\n" ); document.write( "\r\n" ); document.write( "Answer. The natural domain is the set {x | x >= 2}.\r\n" ); document.write( "\r \n" ); document.write( "\n" ); document.write( "For example, x= 3 is in the domain, while x = 1 is not.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |