document.write( "Question 1060072: 1100/(1+99e^-0.3x)=275 (solving for x!) \n" ); document.write( "

Algebra.Com's Answer #675076 by josmiceli(19441) $\"\"$ $\"About$

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$\"+1100+%2F+%28+1+%2B+99%2Ae%5E%28-.3x+%29+%29+=+275+\"$
\n" ); document.write( " $\"+1+%2B+99%2Ae%5E%28-.3x+%29+=+1100%2F275+\"$
\n" ); document.write( " $\"+99%2Ae%5E%28-.3x+%29+=+4+-+1+\"$
\n" ); document.write( " $\"+e%5E%28+-.3x+%29+=+1%2F33+\"$
\n" ); document.write( "Take the natural log of both side
\n" ); document.write( " $\"+-.3x+=+ln%281%29+-+ln%2833%29+\"$
\n" ); document.write( " $\"+-.3x+=+-3.4965+\"$
\n" ); document.write( " $\"+x+=+11.655+\"$
\n" ); document.write( "---------------------
\n" ); document.write( "check answer:
\n" ); document.write( " $\"+1100+%2F+%28+1+%2B+99%2Ae%5E%28-.3%2A11.655+%29+%29+=+275+\"$
\n" ); document.write( " $\"+1100+%2F+%28+1+%2B+99%2Ae%5E%28-3.4965+%29+%29+=+275+\"$
\n" ); document.write( " $\"+1100+%2F+%28+1+%2B+99%2A.030303+%29+=+275+\"$
\n" ); document.write( " $\"+1+%2B+3+=+1100%2F275+\"$
\n" ); document.write( " $\"+4+=+4+\"$
\n" ); document.write( "OK \n" ); document.write( "

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