document.write( "Question 1060017: How to find the exact value of cos(arctan(-5/3)) by using a reference triangle? \n" ); document.write( "
Algebra.Com's Answer #675064 by Alan3354(69443)\"\" \"About 
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How to find the exact value of cos(arctan(-5/3)) by using a reference triangle?
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\n" ); document.write( "Tangent = y/x
\n" ); document.write( "terminal point is (3,-5) in Q4
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\n" ); document.write( "r = sqrt(x^2 + y^2) = sqrt(43)
\n" ); document.write( "cos = x/r = 3/sqrt(34) = 3sqrt(34)/34
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