document.write( "Question 1060007: A 51-acre field yields 1224 bushels of wheat annually. How many additional acres must be planted so that the annual yield will be 1560 bushels? \n" ); document.write( "

Algebra.Com's Answer #675048 by acw1213(28) $\"\"$ $\"About$

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Write a proportional here.
\n" ); document.write( "The fractions will be part over whole.
\n" ); document.write( "Bushels will subside in the denominator of the fractions.\r
\n" ); document.write( "\n" ); document.write( " $\"+51%2F1224+=+x%2F1560\"$ \r
\n" ); document.write( "\n" ); document.write( "Solve for \"x\".
\n" ); document.write( "Cross multiply 51 times 1560 and divide by 1224.
\n" ); document.write( "51*1560 = 79,560
\n" ); document.write( "79,560 / 1224 = 65\r
\n" ); document.write( "\n" ); document.write( "1,560 bushels can be placed in 65 acre fields.\r
\n" ); document.write( "\n" ); document.write( "Great, although, the question asks how many ADDITIONAL acres of field must be planted.\r
\n" ); document.write( "\n" ); document.write( "Subtract the original acre amount from 65 to get the final answer.\r
\n" ); document.write( "\n" ); document.write( "65 - 51 = 14\r
\n" ); document.write( "\n" ); document.write( "14 additional acres must be planted. \n" ); document.write( "

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