document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1059972>Question 1059972</A>: <I><SPAN STYLE=\"word-break: break-all;\"> HELP ME PLS\r<BR>\n" );
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document.write( "A nozzle which is attached to the end of a 4-in fire hose has a length of 1 ft and a diameter at the discharge end of 1 in. If it has a uniform thickness of 5/16 in and is made of brass, find the weight of material used in the manufacture of 1000 such nozzles. (Brass weighs 520 lb per cu. ft)  </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #675024 by </B><A HREF=/tutors/aboutme.mpl?userid=Alan3354><B>Alan3354(69443)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Alan3354><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Alan3354><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=675024\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> A nozzle which is attached to the end of a 4-in fire hose has a length of 1 ft and a diameter at the discharge end of 1 in. If it has a uniform thickness of 5/16 in and is made of brass, find the weight of material used in the manufacture of 1000 such nozzles. (Brass weighs 520 lb per cu. ft) <BR>\n" );
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document.write( "Some details are missing.<BR>\n" );
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document.write( "Assuming it's 2 concentric cones, and that the ID of the end on the hose is 4 inches:<BR>\n" );
document.write( "--> 2 frustums (frusta?) of cones.<BR>\n" );
document.write( "For the outside cone:<BR>\n" );
document.write( "R = large end radius, r = small end radius<BR>\n" );
document.write( "R = 2.3125, r = 0.8125 inches<BR>\n" );
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document.write( "Vol of the frustum = <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=%28pi%2Ah%2F3%29%2A%28R%5E2+%2B+R%2Ar+%2B+r%5E2%29 ALIGN=MIDDLE  ALT=\"%28pi%2Ah%2F3%29%2A%28R%5E2+%2B+R%2Ar+%2B+r%5E2%29\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( "= <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=4pi%2A%282.3125%5E2+%2B+2.3125%2A0.8125+%2B+0.8125%5E2%29 ALIGN=MIDDLE  ALT=\"4pi%2A%282.3125%5E2+%2B+2.3125%2A0.8125+%2B+0.8125%5E2%29\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( "= <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=4pi%2A7.8867 ALIGN=MIDDLE  ALT=\"4pi%2A7.8867\"   DISABLED_style= \"max-width:90%; height:auto;\" > =~ 99.1074 cu inches<BR>\n" );
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document.write( "Subtract the volume of the inside frustum:<BR>\n" );
document.write( "Vol = <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=4pi%2A%282%5E2+%2B+2%2A0.5+%2B+0.5%5E2%29 ALIGN=MIDDLE  ALT=\"4pi%2A%282%5E2+%2B+2%2A0.5+%2B+0.5%5E2%29\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( "= 4pi*5.25 = 21pi =~ 65.973 cu inches<BR>\n" );
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document.write( "33.134 cu inches<BR>\n" );
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document.write( "1 cu ft = 1728 cu inches<BR>\n" );
document.write( "Weight = (33.134/1728)*520<BR>\n" );
document.write( "=~ 9.97 pounds<BR>\n" );
document.write( "x1000 = 9970 pounds (with no scrap) </SPAN>\n" );
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