document.write( "Question 1059970: good morning\r
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\n" ); document.write( "\n" ); document.write( "6+ln(8x)=24-2 ln(x)
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Algebra.Com's Answer #675020 by rothauserc(4718)\"\" \"About 
You can put this solution on YOUR website!
Solve for x over the real numbers
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\n" ); document.write( "6 + ln(8x) = 24 - 2ln(x)
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\n" ); document.write( "Subtract 24 - 2 ln(x) from both sides
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\n" ); document.write( "-18 + 2ln(x) + ln(8x) = 0
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\n" ); document.write( "-18 + 2ln(x) + ln(8x) = -18 + ln(8x) + ln(x^2) = ln(8x^3) - 18
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\n" ); document.write( "Note that c(ln(x)) = ln(x^c) where c is a constant, then we use the product rule of logarithms
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\n" ); document.write( "ln(8x^3) - 18 = 0
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\n" ); document.write( "Add 18 to both sides
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\n" ); document.write( "ln(8x^3) = 18
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\n" ); document.write( "Cancel logarithms by taking exp of both sides, note that ln is natural logarithm
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\n" ); document.write( "8x^3 = e^18
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\n" ); document.write( "Divide both sides by 8
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\n" ); document.write( "x^3 = e^18/8
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\n" ); document.write( "Take cube roots of both sides
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\n" ); document.write( "x = e^6/2
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\n" ); document.write( "Note that e is approximately 2.71828
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\n" ); document.write( "x = (2.71828)^6 / 2 is approximately 201.7144
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