document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=13377>Question 13377</A>: <I><SPAN STYLE=\"word-break: break-all;\"> I’m very confused about solving this problem and its supposed to be solved using substitution. The linear system solve it for me but I need the steps. Thanks <BR>\n" );
document.write( "10x+8y=5<BR>\n" );
document.write( "8x+6y=3<BR>\n" );
document.write( " </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #6750 by </B><A HREF=/tutors/aboutme.mpl?userid=akmb1215><B>akmb1215(68)</B></A><img src=\"/images/stars/stars-08.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=akmb1215><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=6750\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> The easiest way to solve this system of equations is by combination.  You need to figure out the least common multiple of 10 and 8.  This is 40.  To get 40 from 10, you multiply by 4...so multiply the entire top equation by 4 to get <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=40x+%2B+32y+=+20 ALIGN=MIDDLE  ALT=\"40x+%2B+32y+=+20\"   DISABLED_style= \"max-width:90%; height:auto;\" >.  In order to get rid of the x in the combination, you need to get -40x in the second equation.  To get this, multiply the entire equation by -5 to get <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=-40x+-+30y+=+-15 ALIGN=MIDDLE  ALT=\"-40x+-+30y+=+-15\"   DISABLED_style= \"max-width:90%; height:auto;\" >.  Now, you can add the two equations together to get...<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=2y+=+5 ALIGN=MIDDLE  ALT=\"2y+=+5\"   DISABLED_style= \"max-width:90%; height:auto;\" >.  Solve for y to get <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=5%2F2+=+y ALIGN=MIDDLE  ALT=\"5%2F2+=+y\"   DISABLED_style= \"max-width:90%; height:auto;\" >.  To get x, plug this into either equation (I am going to use the top one).  I get <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=10x+%2B+8%282.5%29+=+5 ALIGN=MIDDLE  ALT=\"10x+%2B+8%282.5%29+=+5\"   DISABLED_style= \"max-width:90%; height:auto;\" >.  Multilply to get <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=10x+%2B+20+=+5 ALIGN=MIDDLE  ALT=\"10x+%2B+20+=+5\"   DISABLED_style= \"max-width:90%; height:auto;\" >.  Move 20 to the right side of the equation to get <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=10x+=+-15 ALIGN=MIDDLE  ALT=\"10x+=+-15\"   DISABLED_style= \"max-width:90%; height:auto;\" >.  Divide to get <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=x+=+-15%2F10 ALIGN=MIDDLE  ALT=\"x+=+-15%2F10\"   DISABLED_style= \"max-width:90%; height:auto;\" >, which reduces to <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=x+=+-3%2F2 ALIGN=MIDDLE  ALT=\"x+=+-3%2F2\"   DISABLED_style= \"max-width:90%; height:auto;\" >. </SPAN>\n" );
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