document.write( "Question 1059928: Point \"+A+\" is found at (-3, -3). Locate the tan for that point.
\n" ); document.write( "A.) \"+0+\"
\n" ); document.write( "B.) \"+1+\"
\n" ); document.write( "C.) \"+-1+\"
\n" ); document.write( "D.) \"+1%2F2+\"
\n" ); document.write( "

Algebra.Com's Answer #674967 by stanbon(75887)\"\" \"About 
You can put this solution on YOUR website!
Point \"+A+\" is found at (-3, -3). Locate the tan for that point.
\n" ); document.write( "A.) \"+0+\"
\n" ); document.write( "B.) \"+1+\"
\n" ); document.write( "C.) \"+-1+\"
\n" ); document.write( "D.) \"+1%2F2+\"
\n" ); document.write( "-----------------------
\n" ); document.write( "tan(t) = -3/-3 = 1
\n" ); document.write( "---------
\n" ); document.write( "Since (-3,-3) is in QIII,
\n" ); document.write( "t = arctan(1) = (5/4)pi
\n" ); document.write( "---------------------------------
\n" ); document.write( "Cheers,
\n" ); document.write( "Stan H.
\n" ); document.write( "
\n" );