document.write( "Question 1059840: Could you please help me with binomial theorem. Step by step. I don't understand it. (X to the 3rd power minus the radical of y) to the 8th power. Thank you! \n" ); document.write( "
Algebra.Com's Answer #674962 by MathTherapy(10552)\"\" \"About 
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Could you please help me with binomial theorem. Step by step. I don't understand it. (X to the 3rd power minus the radical of y) to the 8th power. Thank you!
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Is this the same as the one posted earlier? This one is a difference, while the other is a sum. 
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document.write( "Anyway, I'll show you the previous one, and if it's different you should be able to follow the same concept.
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document.write( "There's a little easier way to do this.
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document.write( "\"%28x%5E3+%2B+sqrt%28y%29%29%5E8\", or \"%28x%5E3+%2B+y%5E%281%2F2%29%29%5E8\" 
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document.write( " \"%28a+%2B+b%29%5En\" <======= Compare to this, and you'll see that: a = x3, b = \"sqrt%28y%29\", and n = 8
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document.write( "Since it's a binomial raised to the 8th power you can use the 9th row of PASCAL'S TRIANGLE to get the COMBINATION VALUES for each term. 
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document.write( "That 9th row has the following COMBINATION VALUES:   1      8	  28	   56	    70	    56	   28	  8	 1
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document.write( "                                                     1   +  8  +  28   +   56   +   70   +  56  +  28  +  8   +  1
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document.write( " ------------ Entering values for a and b after each term's COMBINATION VALUE
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document.write( " --- RAISing EACH \"a\" VALUE to the nth power, in descending order
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document.write( " ------- RAISing EACH \"b\" VALUE, starting at the 0th power, up to the nth power
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document.write( " ------- Changing \"matrix%281%2C3%2C+sqrt%28y%29%2C+to%2C+y%5E%281%2F2%29%29\"
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document.write( "Now, SIMPLIFY each term to get:  \n" );
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