document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1059904>Question 1059904</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Solve sec&#920; = -2 for all &#920; such that 0° &#8804; &#920; &#8804;  360°. Round you answers to the nearest degree </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #674957 by </B><A HREF=/tutors/aboutme.mpl?userid=Boreal><B>Boreal(15235)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Boreal><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Boreal><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=674957\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> secant is 1/cos<BR>\n" );
document.write( "Need cosine - 1/2. That is in the second and third quadrants.<BR>\n" );
document.write( "That is at 120 degrees or pi/3 and minus 120 degrees, or 240 degrees (2 pi/3). </SPAN>\n" );
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