document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1059900>Question 1059900</A>: <I><SPAN STYLE=\"word-break: break-all;\"> simplify\r<BR>\n" );
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document.write( "(1/sin^2x)+ (sec^2x/tan^2x)\r<BR>\n" );
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document.write( "Any help is greatly appreciated!  </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #674948 by </B><A HREF=/tutors/aboutme.mpl?userid=Boreal><B>Boreal(15235)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Boreal><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Boreal><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=674948\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> (1/sin^2x)+ (sec^2x/tan^2x); sec^2 x=1/cos^2 x; tan^2 x= sin^2x/cos^2x; sec x/tan x=(1/sin^2 x)<BR>\n" );
document.write( "Therefore, we have (1/sin^2x)+(1/sin^2 x)=2/(sin^2x) </SPAN>\n" );
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