document.write( "Question 1059835: Please help! I have worked on this challenge problem non stop for a while and I can not get a solution! The assignment is due on the 8th of December and I must acquire a Solution please! \r
\n" ); document.write( "\n" ); document.write( "Link: https://www.scribd.com/document/333074965/Challenge-Problem-4\r
\n" ); document.write( "\n" ); document.write( "Here’s the problem:\r
\n" ); document.write( "\n" ); document.write( "You save money in the following way:
\n" ); document.write( "• Jan 1, 2000: Deposit an unknown amount of money into a new account A with an APR of 3% compounded quarterly.
\n" ); document.write( "• Jan 1, 2005: Withdraw all your money from account A and deposit it and an additional $5,000 into a new account B with an APR of 5.5% compounded continuously.
\n" ); document.write( "• Jan 1, 2012: Account B has a balance of $10,078.46.\r
\n" ); document.write( "\n" ); document.write( "Answer the following questions:
\n" ); document.write( "1. What was the amount you deposited into account A on Jan 1, 2000?
\n" ); document.write( "2. What was the earliest date (day, month, and year) when you could have withdrawn $9,000?
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Algebra.Com's Answer #674914 by Edwin McCravy(20060)\"\" \"About 
You can put this solution on YOUR website!
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document.write( "I won't do it for you for that would be totally dishonest, but I'll\r\n" );
document.write( "be a little bit dishonest.  This is what you must solve for P\r\n" );
document.write( "to get the answer to the first part.\r\n" );
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document.write( "\"%28P%281%2B0.03%2F4%29%5E%284%2A5%29%2B5000%29e%5E%280.055%2A7%29\"\"%22%22=%22%22\"\"10078.46\"\r\n" );
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document.write( "To get the answer to the second part, substitute what you\r\n" );
document.write( "get for P in the blank below, replace the 7 by T, and put\r\n" );
document.write( "9000 on the right side, and solve for T. That is, fill in the\r\n" );
document.write( "blank with what you got for P above in this:\r\n" );
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document.write( "\"%28%22_____%22%281%2B0.03%2F4%29%5E%284%2A5%29%2B5000%29e%5E%280.055%2AT%29\"\"%22%22=%22%22\"\"9000\"\r\n" );
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document.write( "The whole part of the number you get for T is the number of full \r\n" );
document.write( "years after Jan 1, 2005. The decimal part is the fraction of the \r\n" );
document.write( "next year after that.\r\n" );
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document.write( "Multiply that decimal part by 365.25 to get the number of days into \r\n" );
document.write( "that next year that the amount was $9000.  Then use the number of \r\n" );
document.write( "days in the various months to find out just what date that was.\r\n" );
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document.write( "Luck to you!\r\n" );
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document.write( "Edwin
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