document.write( "Question 1059759: A doctor wants to estimate the HDL cholesterol of all​ 20- to​ 29-year-old females. How many subjects are needed to estimate the HDL cholesterol within 2 points with 99% confidence assuming σ=10.2? Suppose the doctor would be content with 95 % confidence. How does the decrease in confidence affect the sample size​ required? \n" ); document.write( "
Algebra.Com's Answer #674856 by Boreal(15235)\"\" \"About 
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The interval width is z*sigma/sqrt (n)=2; z(.995)=2.576.
\n" ); document.write( "Square everything
\n" ); document.write( "4=2.576^2*10.2^/n
\n" ); document.write( "N=690.386/4
\n" ); document.write( "=172.59 or 173
\n" ); document.write( "With 95%, z=1.96 and its square is 3.8416
\n" ); document.write( "The smaller value will lessen the numerator and decrease the sample size (to 100).
\n" ); document.write( "Less confidence with no other changes will cause a smaller sample size.
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