document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1059782>Question 1059782</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Hi I am working on Polynomials for homework and I am not sure how to solve this problem here is the problem.\r<BR>\n" );
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document.write( "x^3-3x^2-x+9 for<BR>\n" );
document.write( "a.x=3<BR>\n" );
document.write( "b.x=-3 </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #674836 by </B><A HREF=/tutors/aboutme.mpl?userid=acw1213><B>acw1213(28)</B></A><img src=\"/images/stars/stars-07.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=acw1213><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=acw1213><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=674836\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> For a), plug in 3 for \"x\" in the polynomial and solve using PEMDAS<BR>\n" );
document.write( "(3)^3 - 3(3)^2 - (3) + 9<BR>\n" );
document.write( "27 - 3(9) - 3 + 9<BR>\n" );
document.write( "27 - 27 - 3 + 9<BR>\n" );
document.write( "-3 + 9<BR>\n" );
document.write( "6\r<BR>\n" );
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document.write( "For b), plug in -3 for \"x\" in the polynomial and solve using PEMDAS<BR>\n" );
document.write( "(-3)^3 - 3(-3)^2 - (-3) + 9<BR>\n" );
document.write( "-27 - 3(9) + 3 + 9 <BR>\n" );
document.write( "-27 - 27 + 3 + 9<BR>\n" );
document.write( "-54 + 3 + 9 <BR>\n" );
document.write( "-51 + 9<BR>\n" );
document.write( "-42 </SPAN>\n" );
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