document.write( "Question 1059552: A wooden piece 90 cm long is cut into two pieces of different lengths. The longer piece, a, is used to form a rectangle with width x cm and length y cm, and the shorter piece is used to form a square with side z cm, such that the rectangle and the square have the same areas. Prove that x+y=a/2, and z=(90-a)/4.\r
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Algebra.Com's Answer #674822 by josmiceli(19441)\"\" \"About 
You can put this solution on YOUR website!
The 4 sides of the rectangle, a, are:
\n" ); document.write( "\"+x+%2B+x+%2B+y+%2B+y+=+2x+%2B+2y+\"
\n" ); document.write( "\"+2x+%2B+2y+=+a+\"
\n" ); document.write( "\"+2%2A%28+x+%2B+y+%29+=+a+\"
\n" ); document.write( "\"+x+%2B+y+=+a%2F2+\"
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\n" ); document.write( "The 4 sides of the square add up to:
\n" ); document.write( "\"+z+%2B+z+%2B+z+%2B+z+=+4z+\"
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\n" ); document.write( "If the piece of wood was \"+90+\" cm long
\n" ); document.write( "then \"+4z+=+90+-+a+\"
\n" ); document.write( "\"+z+=+%28+90+-+a+%29+%2F+4+\"
\n" ); document.write( "------------------------
\n" ); document.write( "Hope this helps\r
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