document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1059703>Question 1059703</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The hypotenuse of a right triangle is 10.2 m long. One leg is 2.1 m shorter than the other leg. Find the lengths of the legs. Round to one decimal place.<BR>\n" );
document.write( "So I know it's written as (X)^2 + (X-2.1)^2= (10.2)^2<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #674776 by </B><A HREF=/tutors/aboutme.mpl?userid=rothauserc><B>rothauserc(4718)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=rothauserc><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=rothauserc><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=674776\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> (x)^2 + (x-2.1)^2 = (10.2)^2<BR>\n" );
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document.write( "x^2 +x^2 -4.2x +4.41 = 104.04<BR>\n" );
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document.write( "2x^2 -4.2x -99.63 = 0<BR>\n" );
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document.write( "divide both sides of = by 2<BR>\n" );
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document.write( "x^2 -2.1x -49.185 = 0<BR>\n" );
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document.write( "us quadratic formula to solve for x<BR>\n" );
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document.write( "x = ( -(-2.1) + square root( (-2.1)^2 -4*(-49.185) ) ) / (2*1) = 8.1414<BR>\n" );
document.write( "x = ( -(-2.1) - square root( (-2.1)^2 -4*(-49.185) ) ) / (2*1) = -6.0414<BR>\n" );
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document.write( "We want the positive value x<BR>\n" );
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document.write( "one leg is 8.1 m and the other leg is 6.0 m<BR>\n" );
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document.write( "(8.1)^2 + (6.0)^2 = (10.2)^2<BR>\n" );
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document.write( "65.61 + 36.0 = 104.04<BR>\n" );
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document.write( "101.61 approx 104.04<BR>\n" );
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document.write( "difference is due to rounding of x value<BR>\n" );
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