document.write( "Question 1059621: Ref. Question 1059604 Follow-up: \r
\n" ); document.write( "\n" ); document.write( "A coil of steel wire weighs 50 lbs., diameter 0.025 in. Steel weighs .283 lbs. / cu. in. Determine length of wire. \r
\n" ); document.write( "\n" ); document.write( " The wire is a regular cylinder. \r
\n" ); document.write( "\n" ); document.write( " Area of circle; pi * r^2.
\n" ); document.write( " 3.1416 * 0.0125 * 0.0125 = 0.0049 sq. in.
\n" ); document.write( " 0.0049 * 1 = 0.0049 cu. in. (volume of 1 ft.)
\n" ); document.write( " 50 / .283 = 176.678 = 177 cu. in. (vol. of wire).
\n" ); document.write( " 177 / 0.0049 = 36122.48 ft.
\n" ); document.write( " Answer given is less. Where am I incorrect ? Thanks.\r
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\n" ); document.write( "\n" ); document.write( "I don't understand your L = .
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Algebra.Com's Answer #674768 by Fombitz(32388)\"\" \"About 
You can put this solution on YOUR website!
0.0049 * 1 = 0.0049 cu. in. (volume of 1 ft.) <--- Mistake in this line
\n" ); document.write( "1 foot equals 12 inches, you mixed your units up.
\n" ); document.write( "Should be,
\n" ); document.write( "0.0049*12
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