document.write( "Question 1059714: How do I solve this system using an augmented matrix?\r
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document.write( "–x – 3y = –17
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document.write( "2x – 6y = –26 \n" );
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Algebra.Com's Answer #674750 by ikleyn(52847)![]() ![]() You can put this solution on YOUR website! . \n" ); document.write( "How do I solve this system using an augmented matrix?\r \n" ); document.write( "\n" ); document.write( "–x – 3y = –17 \n" ); document.write( "2x – 6y = –26 \n" ); document.write( "~~~~~~~~~~~~~~~~~~~\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Solution set:\r \n" ); document.write( "\n" ); document.write( " \r\n" ); document.write( "x1 = 2\r\n" ); document.write( "x2 = 5\r\n" ); document.write( "\r \n" ); document.write( "\n" ); document.write( " \r\n" ); document.write( "Your matrix\r\n" ); document.write( "\r\n" ); document.write( "№ X1 X2 b\r\n" ); document.write( "1 -1 -3 -17\r\n" ); document.write( "2 2 -6 -26\r\n" ); document.write( "\r\n" ); document.write( "Find the pivot in the 1st column in the 1st row (inversing the sign in the whole row)\r\n" ); document.write( "\r\n" ); document.write( "№ X1 X2 b\r\n" ); document.write( "1 1 3 17\r\n" ); document.write( "2 2 -6 -26\r\n" ); document.write( "\r\n" ); document.write( "Multiply the 1st row by 2\r\n" ); document.write( "\r\n" ); document.write( "№ X1 X2 b\r\n" ); document.write( "1 2 6 34\r\n" ); document.write( "2 2 -6 -26\r\n" ); document.write( "\r\n" ); document.write( "Subtract the 1st row from the 2nd row and restore it\r\n" ); document.write( "\r\n" ); document.write( "№ X1 X2 b\r\n" ); document.write( "1 1 3 17\r\n" ); document.write( "2 0 -12 -60\r\n" ); document.write( "\r\n" ); document.write( "Make the pivot in the 2nd column by dividing the 2nd row by -12\r\n" ); document.write( "\r\n" ); document.write( "№ X1 X2 b\r\n" ); document.write( "1 1 3 17\r\n" ); document.write( "2 0 1 5\r\n" ); document.write( "\r\n" ); document.write( "Multiply the 2nd row by 3\r\n" ); document.write( "\r\n" ); document.write( "№ X1 X2 b\r\n" ); document.write( "1 1 3 17\r\n" ); document.write( "2 0 3 15\r\n" ); document.write( "\r\n" ); document.write( "Subtract the 2nd row from the 1st row and restore it\r\n" ); document.write( "\r\n" ); document.write( "№ X1 X2 b\r\n" ); document.write( "1 1 0 2\r\n" ); document.write( "2 0 1 5\r\n" ); document.write( " \n" ); document.write( " \n" ); document.write( " |