document.write( "Question 1059706: Solve the equation by completing the square and applying the square root property. Write imaginary solutions in the form a+bį.
\n" ); document.write( "2a^2+4a+5=0
\n" ); document.write( "2a^2+4a=-5
\n" ); document.write( "((2a^2)/2)+(4a/2))=(-5/2)
\n" ); document.write( "(1/2(2)^2)=1
\n" ); document.write( "a^2+2a+1=-5/2+1
\n" ); document.write( "(a+1)^2=(-5/2)+(2/2)
\n" ); document.write( "(a+1)^2=-3/2
\n" ); document.write( "sqrt (a+1)^2=sqrt(-3/2)
\n" ); document.write( "a+1=+or- sqrt(3/2)į \n" ); document.write( "

Algebra.Com's Answer #674744 by MathTherapy(10552) $\"\"$ $\"About$

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Solve the equation by completing the square and applying the square root property. Write imaginary solutions in the form a+bį.
\n" ); document.write( "2a^2+4a+5=0
\n" ); document.write( "2a^2+4a=-5
\n" ); document.write( "((2a^2)/2)+(4a/2))=(-5/2)
\n" ); document.write( "(1/2)(2)^2) = 1
\n" ); document.write( "a^2+2a+1=-5/2+1
\n" ); document.write( "(a+1)^2=(-5/2)+(2/2)
\n" ); document.write( "(a+1)^2=-3/2
\n" ); document.write( "sqrt (a+1)^2=sqrt(-3/2)
\n" ); document.write( "a+1=+or- sqrt(3/2)į
\n" ); document.write( "

 
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document.write( " <======== Correct
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document.write( " <======= Correct
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document.write( " <======= Correct
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document.write( " <======= Correct
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document.write( "I must say, so far, I'm impressed
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document.write( " <===== Correct
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document.write( " <====== Correct
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document.write( " <====== Correct
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document.write( " =====>  =====>  \n" );
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