document.write( "Question 1059606: The width of a rectangle is 1 inch less than twice the side of a square. the length of a rectangle is three times the side of the square. if the area of the rectangle is 36 in.² more than the area of the square then find the side of the square \n" ); document.write( "
Algebra.Com's Answer #674738 by josgarithmetic(39617)![]() ![]() ![]() You can put this solution on YOUR website! Same rectangle? Dimensions w and L. \n" ); document.write( "Let the side length for the square be x.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Minor simplification, \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Substitutions into the area equation: \n" ); document.write( " \n" ); document.write( "and you can simplify and solve this. \n" ); document.write( " |