document.write( "Question 1059606: The width of a rectangle is 1 inch less than twice the side of a square. the length of a rectangle is three times the side of the square. if the area of the rectangle is 36 in.² more than the area of the square then find the side of the square \n" ); document.write( "
Algebra.Com's Answer #674738 by josgarithmetic(39617)\"\" \"About 
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Same rectangle? Dimensions w and L.
\n" ); document.write( "Let the side length for the square be x.\r
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\n" ); document.write( "\n" ); document.write( "\"system%28w=-1%2B2x%2CL=3x%2CwL=36%2Bx%5E2%29\"\r
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\n" ); document.write( "\n" ); document.write( "Minor simplification, \"system%28w=2x-1%2CL=3x%2CwL=x%5E2%2B36%29\"\r
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\n" ); document.write( "\n" ); document.write( "Substitutions into the area equation:
\n" ); document.write( "\"%282x-1%29%283x%29=x%5E2%2B36\"
\n" ); document.write( "and you can simplify and solve this.
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