document.write( "Question 1059638: The first car is going 40mi/h,and the second car is going 55mi/h.the first car left 3 hours before the second car.what equation could you use to find how many hours it will take for the second car to catch up to the first car? \n" ); document.write( "

Algebra.Com's Answer #674735 by ikleyn(53763) $\"\"$ $\"About$

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\n" ); document.write( "The first car is going 40 mi/h,and the second car is going 55 mi/h.the first car left 3 hours before the second car.
\n" ); document.write( "what equation could you use to find how many hours it will take for the second car to catch up to the first car?
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\n" ); document.write( "\n" ); document.write( "Everything is in these 4 lines below.\r
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document.write( "Time to catch =  =  = 8 hours.\r\n" );
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document.write( "The numerator 3*40 = 120 kilometers is the distance for the first car to be ahead at the moment the second car started.\r\n" );
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document.write( "The difference (55-40) in the denominator is the rate of decreasing the distance between two cars. \r\n" );
document.write( "It is their relative speed.\r\n" );
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document.write( "That's all.\r\n" );
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\n" ); document.write( "\n" ); document.write( "You should be able to write such an equation instantly as you read and understand the problem.\r
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\n" ); document.write( "\n" ); document.write( "Producing tables is not the way solving such problems.\r
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