document.write( "Question 1059648: The outside of a picture frame measures 14 in by 20 in. 172 in^2 of the picture shows. Find the thickness of the frame.
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Algebra.Com's Answer #674732 by josmiceli(19441) $\"\"$ $\"About$

You can put this solution on YOUR website!
Let $\"+x+\"$ = the thickness of the frame
\n" ); document.write( " $\"+%28+14+-+2x+%29%2A%28+20+-+2x+%29+=+172+\"$
\n" ); document.write( " $\"+280+-+40x+-+28x+%2B+4x%5E2+=+172+\"$
\n" ); document.write( " $\"+4x%5E2+-+68x+%2B+280+=+172+\"$
\n" ); document.write( " $\"+4x%5E2+-+68x+%2B+108+=+0+\"$
\n" ); document.write( " $\"x%5E2+-+17x+%2B+27+=+0+\"$
\n" ); document.write( " $\"+x+=+%28+-b+%2B-+sqrt%28+b%5E2+-+4%2Aa%2Ac+%29%29+%2F+%282%2Aa%29+\"$
\n" ); document.write( " $\"+a+=+1+\"$
\n" ); document.write( " $\"+b+=+-17+\"$
\n" ); document.write( " $\"+c+=+27+\"$
\n" ); document.write( " $\"+x+=+%28+-%28-17%29+%2B-+sqrt%28+%28-17%29%5E2+-+4%2A1%2A27+%29%29+%2F+%282%2A1%29+\"$
\n" ); document.write( " $\"+x+=+%28+17+%2B-+sqrt%28+289+-+108+%29%29+%2F+2+\"$
\n" ); document.write( " $\"+x+=+%28+17+%2B-+sqrt%28+181+%29%29+%2F+2+\"$
\n" ); document.write( " $\"+x+=+%28+17+-+13.4536+%29+%2F+2+\"$ ( note the + sqrt gives too big a number )
\n" ); document.write( " $\"+x+=+3.5464+%2F+2+\"$
\n" ); document.write( " $\"+x+=+1.7732+\"$
\n" ); document.write( "The thickness of the frame is 1.7732 in.
\n" ); document.write( "---------------
\n" ); document.write( "check:
\n" ); document.write( " $\"+%28+14+-+2x+%29%2A%28+20+-+2x+%29+=+172+\"$
\n" ); document.write( " $\"+%28+14+-+2%2A1.7732+%29%2A%28+20+-+2%2A1.7732+%29+=+172+\"$
\n" ); document.write( " $\"+%28+14+-+3.5464+%29%2A%28+20+-+3.5464+%29+=+172+\"$
\n" ); document.write( " $\"+10.4536%2A16.4536+=+172+\"$
\n" ); document.write( " $\"+171.9993+=+172+\"$
\n" ); document.write( "close enough\r
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