document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1059568>Question 1059568</A>: <I><SPAN STYLE=\"word-break: break-all;\"> If the perimeter of a rectangle is 54 cm and the area is 182 square cm, then what are the dimensions of the rectangle? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #674692 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=674692\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> If the perimeter of a rectangle is 54 cm and the area is 182 square cm, then what are the dimensions of the rectangle? <BR>\n" );
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document.write( "54 = 2(L + W)<BR>\n" );
document.write( "L*W = 182<BR>\n" );
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document.write( "L + W = 27<BR>\n" );
document.write( "L = 27-W<BR>\n" );
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document.write( "Substitute for \"L\" and solve for \"W\"::<BR>\n" );
document.write( "(27-W)W = 182<BR>\n" );
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document.write( "-W^2 + 27W - 182 = 0<BR>\n" );
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document.write( "W^2 - 27W + 182 = 0<BR>\n" );
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document.write( "W = 32.59 (Width)<BR>\n" );
document.write( "L = 182/32.59 = 5.58 (Length)<BR>\n" );
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document.write( "Cheers,<BR>\n" );
document.write( "Stan H. </SPAN>\n" );
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