document.write( "Question 1059614: A local civic theater has 22 seats in the first row and 21 rows in all. Each successive row contains 3 additional seats. How many seats are in the civic theater?
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document.write( "a.) 1092
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document.write( "b.) 1010
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document.write( "c.) 1070
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document.write( "d.) 790 \n" );
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Algebra.Com's Answer #674663 by Boreal(15235)![]() ![]() You can put this solution on YOUR website! sum of the 21 rows, s21=21/2(22+sn), where the last row, 20th back, has 60 more seats or 82. \n" ); document.write( "Therefore, s21=21/2(22+82)=21/2(104)=1092 seats. The formula takes the first and the last and uses that as an average, multiplying by the number of rows. \n" ); document.write( "22+25+28+31=116 \n" ); document.write( "34+37+40+43=154 \n" ); document.write( "46+49+52+55=202 \n" ); document.write( "58+61+64+67=250 \n" ); document.write( "70+73+76+79=298 \n" ); document.write( "82==========82 \n" ); document.write( "That equals 1092. \n" ); document.write( " |