document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=92654>Question 92654</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Solve by completing the square:\r<BR>\n" );
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document.write( "y^2-6y-8=0\r<BR>\n" );
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document.write( "Your help is truly appreciated! Thanks! </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #67466 by </B><A HREF=/tutors/aboutme.mpl?userid=ankor@dixie-net.com><B>ankor@dixie-net.com(22740)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=ankor@dixie-net.com><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=ankor@dixie-net.com><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=67466\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Solve by completing the square:<BR>\n" );
document.write( "y^2 - 6y - 8 = 0 <BR>\n" );
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document.write( "y^2 - 6y + ___ = + 8<BR>\n" );
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document.write( "Complete the square;<BR>\n" );
document.write( "y^2 - 6y + 9 = 8 + 9<BR>\n" );
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document.write( "(y - 3)^2 = 17<BR>\n" );
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document.write( "Find the square root of both sides:<BR>\n" );
document.write( "y - 3 = +/-Sqrt(17)<BR>\n" );
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document.write( "y = 3 + Sqrt(17)<BR>\n" );
document.write( "and<BR>\n" );
document.write( "y = 3 - Sqrt(17)<BR>\n" );
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document.write( "Did this help, any questions<BR>\n" );
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