document.write( "Question 1059605: Prove that if 1 is added to the product of any four
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Algebra.Com's Answer #674657 by ikleyn(52800)\"\" \"About 
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document.write( "The problem asks us to prove that n*(n+1)*(n+2)*(n+3) + 1 is a square of an integer.\r\n" );
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document.write( "Let x = \"%28n%2B1%29+%2B+1%2F2\" be the central point for the original four integers n, n+1, n+2 and n+3.  Then\r\n" );
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document.write( "  n*(n+1)*(n+2)*(n+3) + 1 = (x+0.5)*(x-0.5)*(x+1.5)*(x-1.5) + 1 = \r\n" );
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document.write( "= \"%28x%5E2-0.25%29%2A%28x%5E2-2.25%29+%2B+1\" = \"x%5E4+-+2.5x%5E2+%2B+%282.25%2F4%29+%2B+1\" = \r\n" );
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document.write( "= \"x%5E4+-+2.5x%5E2+%2B+6.25%2F4\" = \"%28x%5E2-2.5%2F2%29%5E2\".\r\n" );
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document.write( "Next,  \"x%5E2+-+2.5%2F2\" = (by the definition of \"x\") = \"%28n%2B1%29%5E2+%2B+%28n%2B1%29+%2B+%281%2F2%29%5E2+-+5%2F4\" = \"%28n%2B1%29%5E2+%2B+%28n%2B1%29+-+1\"  is the integer number.\r\n" );
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document.write( "Thus we proved that  n*(n+1)*(n+2)*(n+3) + 1  is the square of the integer number  \"%28n%2B1%29%5E2+%2B+%28n%2B1%29+-+1\" = \"%28n%2B1%29%5E2+%2B+n\".\r\n" );
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