document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=92673>Question 92673</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Mike and Adam left a bus terminal at the same time and traveled in opposite directions. Mike's bus was in heavy traffic and had to travel 20mi/h slower than Adam's bus. After 3 hours, their buses were 270 miles apart. How fast was each bus going?\r<BR>\n" );
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document.write( "It's the after 3hrs that confuse me. Can you help?<BR>\n" );
document.write( "Kim </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #67463 by </B><A HREF=/tutors/aboutme.mpl?userid=checkley75><B>checkley75(3666)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=checkley75><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=67463\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> 270=3*X+3(X-20) MILEAGE=R*T+R*T.<BR>\n" );
document.write( "270=3X+3X-60<BR>\n" );
document.write( "6X=270+60<BR>\n" );
document.write( "6X=330<BR>\n" );
document.write( "X=330/6<BR>\n" );
document.write( "X=55 MPH FOR ADAM'S SPEED.<BR>\n" );
document.write( "55-20=35 MPH FOR MIKE'S SPEED.<BR>\n" );
document.write( "PROOF'270=3*55+3*35<BR>\n" );
document.write( "270=165+105<BR>\n" );
document.write( "270=270<BR>\n" );
document.write( "  </SPAN>\n" );
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