document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1059589>Question 1059589</A>: <I><SPAN STYLE=\"word-break: break-all;\"> 3(5x+6)+5x+ 11 = 8x+53 </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #674627 by </B><A HREF=/tutors/aboutme.mpl?userid=jjirinec><B>jjirinec(1)</B></A><img src=\"/images/stars/iconNewId_16x16.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=jjirinec><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=674627\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Hi There,<BR>\n" );
document.write( "So lets start by distributing the 3 across the (5x+6) giving us 15x + 18.<BR>\n" );
document.write( "Now we have 15x+18+5x+11=8x+53,<BR>\n" );
document.write( "Next we should combine like terms on each side of the equation which will give us 20x+29=8x+53. <BR>\n" );
document.write( "Now we should subtract the 8x from the right side, and the 29 from the left side we are left with 12x=24.<BR>\n" );
document.write( "Then we should divide by 12 to get x by itself, which leaves us with x=2.<BR>\n" );
document.write( "Now we can plug 2 back into the original equation for x.<BR>\n" );
document.write( "This gives us 3(5(2)+6)+5(2)+11=8(2)+53.<BR>\n" );
document.write( "We then can simplify down to 3(10+6)+10+11=16+53.<BR>\n" );
document.write( "Then continue PEMDAS, to get 3(16)+21=69.<BR>\n" );
document.write( "Then Multiply 3 and 16 to get 48+21+69<BR>\n" );
document.write( "Finally it checks 69=69. Hope This helps! </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );