document.write( "Question 1059512: Amy was born when Phil was 24 years old.
\n" ); document.write( "When Amy is 3 times as old as she is today, Phil will be 3 times as old as Amy.
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Algebra.Com's Answer #674577 by josmiceli(19441)\"\" \"About 
You can put this solution on YOUR website!
Let \"+a+\" = Amy's age now
\n" ); document.write( "Let \"+b+\" = Phil's age now
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\n" ); document.write( "The difference in their ages will
\n" ); document.write( "ALWAYS be \"+24+\" yrs
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\n" ); document.write( "(1) \"+b+=+a+%2B+24+\"
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\n" ); document.write( "Note that \"+3a+=+a+%2B+2a+\"
\n" ); document.write( "If I add \"+2a+\" to Amy's age, I
\n" ); document.write( "must add it to Phil's, so this
\n" ); document.write( "is what I get:
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\n" ); document.write( "(2) \"+b+%2B+2a+=+3%2A%28+a+%2B+2a+%29+\"
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\n" ); document.write( "(2) \"+b+%2B+2a+=+9a+\"
\n" ); document.write( "(2) \"+b+=+7a+\"
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\n" ); document.write( "By substitution:
\n" ); document.write( "(1) \"+7a+=+a+%2B+24+\"
\n" ); document.write( "(1) \"+6a+=+24+\"
\n" ); document.write( "(1) \"+a+=+4+\"
\n" ); document.write( "and
\n" ); document.write( "(1) \"+b+=+a+%2B+24+\"
\n" ); document.write( "(1) \"+b+=+4+%2B+24+\"
\n" ); document.write( "(1) \"+b+=+28+\"
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\n" ); document.write( "Phil is 28 now
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\n" ); document.write( "check:
\n" ); document.write( "When Amy is 3 times as old as she is today, or
\n" ); document.write( "when she is \"+3%2A4+=+12+\"
\n" ); document.write( "Phil will be \"+12+%2B+24+=+36+\"
\n" ); document.write( "and \"+36+=+3%2A12+\"
\n" ); document.write( "OK\r
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