document.write( "Question 1059533: Amy was born when Phil was 24 years old.
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Algebra.Com's Answer #674572 by ikleyn(52794)\"\" \"About 
You can put this solution on YOUR website!
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\n" ); document.write( "Amy was born when Phil was 24 years old.
\n" ); document.write( "When Amy is 3 times as old as she is today, Phil will be 3 times as old as Amy.
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document.write( "Let A be Amy's present age, P be Phil's present age.\r\n" );
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document.write( "Then the first equation is\r\n" );
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document.write( "A = P - 24.       (1)     (\"Amy was born when Phil was 24 years old.\")\r\n" );
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document.write( "When Amy will be 3 times as old as she is today ?  -  In 2A years.\r\n" );
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document.write( "At that time (\"in 2A years\") Phil's age will be (P + 2A).\r\n" );
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document.write( "Hence, the second equation is\r\n" );
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document.write( "3(3A) = P + 2A.    (2)     (\"When Amy is 3 times as old as she is today, Phil will be 3 times as old as Amy.\")\r\n" );
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document.write( "From (2), 7A = P.\r\n" );
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document.write( "Now substitute this expression P = 7A into (1). You will get\r\n" );
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document.write( "A = 7A - 24  --->  24 = 6A  --->  A =  \"24%2F6\" = 4.\r\n" );
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document.write( "Answer.  Ami's current age is 4 years. Phil's present age is P =A + 24 = 4 + 24 = 28 years.\r\n" );
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\n" ); document.write( "There was a mistake in my original post.
\n" ); document.write( "Now I fixed it and changed my post after seeing the correct solution by the tutor \"josmiseli\".\r
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\n" ); document.write( "\n" ); document.write( "Sorry for my mistake.\r
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\n" ); document.write( "\n" ); document.write( "Thanks to \"josmiseli\".\r
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