document.write( "Question 1059430: Solving system using TI Nspire
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document.write( "2a-b=1
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document.write( "5a-3b=0 \n" );
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Algebra.Com's Answer #674516 by acw1213(28)![]() ![]() You can put this solution on YOUR website! Not sure what you mean by TI Nspire. \n" ); document.write( "You can use elimination here. \n" ); document.write( "Multiply the first equation by 3. \n" ); document.write( "3(2a - b = 1) \n" ); document.write( "Your system is now: \n" ); document.write( "6a - 3b = 3 \n" ); document.write( "5a - 3b = 0 \n" ); document.write( "Look at your coefficients. Are there any opposite signs or same signs? \n" ); document.write( "YES! The \"b\"s have the same coefficients. \n" ); document.write( "This means to ADD the equations. \n" ); document.write( "The \"b\"s cancel out now. \n" ); document.write( "11a = 3 \n" ); document.write( "Divide by 11 on both sides \n" ); document.write( "a = 3/11\r \n" ); document.write( "\n" ); document.write( "Plug in 3/11 for \"a\" in either equation and solve for \"b\" \n" ); document.write( "5(3/11) - 3b = 0 \n" ); document.write( "15/11 - 3b = 0 \n" ); document.write( "Subtract 15/11 on both sides \n" ); document.write( "-3b = -15/11 \n" ); document.write( "Divide by -3 on both sides. \n" ); document.write( "b = 15/33\r \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |