document.write( "Question 1059463: The sum of the ages of Mark's two sons is equal to his own age of 51.
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document.write( "21 years ago, Mark's older son was twice as old as the younger son.
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document.write( "How old was Mark when the sum of his sons' ages was half his age? \n" );
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Algebra.Com's Answer #674512 by jorel555(1290)![]() ![]() ![]() You can put this solution on YOUR website! Let Mark's older son be m, and his younger son be n. Then \n" ); document.write( "m+n=51 \n" ); document.write( "m=51-n \n" ); document.write( "and \n" ); document.write( "m-21=2(n-21), So: \n" ); document.write( "51-n-21=2n-42 \n" ); document.write( "3n=72 \n" ); document.write( "n=24 \n" ); document.write( "Let p be the number of years ago that m and n together made half his age. Then \n" ); document.write( "51-p=2(24-p+27-p) \n" ); document.write( "51-p=48+54-4p \n" ); document.write( "3p=51 \n" ); document.write( "p=17 \n" ); document.write( "17 years ago, Mark was twice as old as his sons combined. ☺☺☺☺ \n" ); document.write( " \n" ); document.write( " |