document.write( "Question 1059463: The sum of the ages of Mark's two sons is equal to his own age of 51.
\n" ); document.write( "21 years ago, Mark's older son was twice as old as the younger son.
\n" ); document.write( "How old was Mark when the sum of his sons' ages was half his age?
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Algebra.Com's Answer #674512 by jorel555(1290)\"\" \"About 
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Let Mark's older son be m, and his younger son be n. Then
\n" ); document.write( "m+n=51
\n" ); document.write( "m=51-n
\n" ); document.write( "and
\n" ); document.write( "m-21=2(n-21), So:
\n" ); document.write( "51-n-21=2n-42
\n" ); document.write( "3n=72
\n" ); document.write( "n=24
\n" ); document.write( "Let p be the number of years ago that m and n together made half his age. Then
\n" ); document.write( "51-p=2(24-p+27-p)
\n" ); document.write( "51-p=48+54-4p
\n" ); document.write( "3p=51
\n" ); document.write( "p=17
\n" ); document.write( "17 years ago, Mark was twice as old as his sons combined. ☺☺☺☺
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