document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=92506>Question 92506</A>: <I><SPAN STYLE=\"word-break: break-all;\"> A closed tube is 10 inches long with a radius of 5 inches <BR>\n" );
document.write( "find its surface area <BR>\n" );
document.write( "find its volume </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #67449 by </B><A HREF=/tutors/aboutme.mpl?userid=ankor@dixie-net.com><B>ankor@dixie-net.com(22740)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=ankor@dixie-net.com><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=ankor@dixie-net.com><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=67449\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> A closed tube is 10 inches long with a radius of 5 inches<BR>\n" );
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document.write( "find its surface area<BR>\n" );
document.write( "Area of the side: circumference * length<BR>\n" );
document.write( "Area of the ends: 2 * area of the circular ends<BR>\n" );
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document.write( "A = Side area + 2 ends area<BR>\n" );
document.write( "A = (2*pi*5*10) + 2(pi*5^2)<BR>\n" );
document.write( "A =    314.16 + 157.08<BR>\n" );
document.write( "A = 471.4 cu inches<BR>\n" );
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document.write( "find its volume<BR>\n" );
document.write( "Vol = pi*r^2*h<BR>\n" );
document.write( "V = pi*5^2*10<BR>\n" );
document.write( "V = 785.4 cu inches </SPAN>\n" );
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