document.write( "Question 1059381: It says factor f(x) into linear factors given that k is a zero of f(x), f(x)=4x^3+11x^2-115=28 k=4 . Can you help me? My teacher has not gone over this and I do not know how to do it and I have a Final Exam in my class Friday. Thank you very much!!!!! \n" ); document.write( "
Algebra.Com's Answer #674415 by rothauserc(4718)\"\" \"About 
You can put this solution on YOUR website!
f(x) = 4x^3 +11x^2 -115 = 28, and k = 4 is a zero
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\n" ); document.write( "where is k in f(x)?
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\n" ); document.write( "Let's check x = 4 is a zero of f(x)
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\n" ); document.write( "rewrite f(x)
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\n" ); document.write( "4x^3 +11x^2 -115 -28 = 0
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\n" ); document.write( "4x^3 +11x^2 -143 = 0
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\n" ); document.write( "If we substitute x=4, we should get 0
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\n" ); document.write( "4(4^3) +11(4^2) - 143 = 0
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\n" ); document.write( "256 +176 -143 = 0
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\n" ); document.write( "432 -143 = 0
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\n" ); document.write( "289 does not = 0
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\n" ); document.write( "x = 4, is not a zero of f(x)
\n" ); document.write( "Do you have f(x) correctly stated?
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