document.write( "Question 1059345: Determine number of lead balls in a lb. if the diameter is 1/4 inch. Lead weighs .41 lbs. / cu. in.\r
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\n" ); document.write( "\n" ); document.write( "16 oz. = 1 lb.\r
\n" ); document.write( "\n" ); document.write( "Volume of sphere; 4/3 * pi * r^3\r
\n" ); document.write( "\n" ); document.write( "1.333 * 3.1416 *.125 * .125 * .125 =.00081 cu. in.\r
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Algebra.Com's Answer #674394 by josgarithmetic(39623)\"\" \"About 
You can put this solution on YOUR website!
\"1%2F8\" of an inch is the radius of a lead ball, and given density is \"0.41%28pounds%2Fcubicinch%29\".\r
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\n" ); document.write( "\n" ); document.write( "How many of these lead balls in ONE POUND?\r
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\n" ); document.write( "\n" ); document.write( "Find first the volume of 1 lead ball.
\n" ); document.write( "\"%284%2F3%29pi%281%2F8%29%5E3\", cubic inches.\r
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\n" ); document.write( "\n" ); document.write( "-------understand that the \"pi\" appears out-of-place and is a FACTOR; not an exponent.\r
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\n" ); document.write( "\n" ); document.write( "That is completely unsimplified, so what is still needing be done is to simplify it.
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