document.write( "Question 1059311: In still​ water, a boat averages 18 miles per hour. It takes the same amount of
\n" ); document.write( "time to travel 16 miles ​downstream, with the​ current, as it does 8 miles​ upstream,
\n" ); document.write( "against the current. What is the rate of the​ water's current?
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Algebra.Com's Answer #674366 by josmiceli(19441)\"\" \"About 
You can put this solution on YOUR website!
Let \"+c+\" = the rate of the current in hrs
\n" ); document.write( "Let \"+t+\" = the time in hrs to go either
\n" ); document.write( "downstream or upstream
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\n" ); document.write( "Going downstream:
\n" ); document.write( "(1) \"+16+=+%28+18+%2B+c+%29%2At+\"
\n" ); document.write( "Going upstream:
\n" ); document.write( "(2) \"+8+=+%28+18+-+c+%29%2At+\"
\n" ); document.write( "-----------------------
\n" ); document.write( "(1) \"+t+=+16+%2F+%28+18+%2B+c+%29+\"
\n" ); document.write( "Plug (1) into (2)
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\n" ); document.write( "(2) \"+8+=+%28+18+-+c+%29%2A%28+16+%2F+%28+18+%2B+c+%29+%29+\"
\n" ); document.write( "(2) \"+8%2A%28+18+%2B+c+%29+=+16%2A%28+18+-+c+%29+\"
\n" ); document.write( "(2) \"+144+%2B+8c+=+288+-+16c+\"
\n" ); document.write( "(2) \"+24c+=+144+\"
\n" ); document.write( "(2) \"+c+=+6+\"
\n" ); document.write( "-------------------
\n" ); document.write( "The rate of the current is 6 mi/hr\r
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