document.write( "Question 1059111: Find three consecutive numbers such that three times the first number is equal to the sum of the other two \n" ); document.write( "

Algebra.Com's Answer #674251 by solve_for_x(190) $\"\"$ $\"About$

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Let x represent the first of the three numbers.\r
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\n" ); document.write( "\n" ); document.write( "The next two consecutive numbers (assumed to be integers) are x + 1 and x + 2.\r
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\n" ); document.write( "\n" ); document.write( "Since \"three times the first number is equal to the sum of the other two\", you can write:\r
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\n" ); document.write( "\n" ); document.write( "3x = (x + 1) + (x + 2)\r
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\n" ); document.write( "\n" ); document.write( "3x = 2x + 3\r
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\n" ); document.write( "\n" ); document.write( "3x - 2x = 3\r
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\n" ); document.write( "\n" ); document.write( "x = 3\r
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\n" ); document.write( "\n" ); document.write( "The three numbers are then:\r
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\n" ); document.write( "\n" ); document.write( "x = 3\r
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\n" ); document.write( "\n" ); document.write( "x + 1 = 3 + 1 = 4\r
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\n" ); document.write( "\n" ); document.write( "x + 2 = 3 + 2 = 5\r
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\n" ); document.write( "\n" ); document.write( "Solution: The numbers are 3, 4, and 5. \n" ); document.write( "

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