document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=92613>Question 92613</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Please help me with this problem:\r<BR>\n" );
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document.write( "Solve the following absolute value inequalities:<BR>\n" );
document.write( "The absolute value of (x+1)is less than or equal to the absolute value of (x-3).\r<BR>\n" );
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document.write( "I'm sorry I don't know how to key in a problem like that.  I know how to solve a problem with absoulute value on one side, but does that same concept apply?  Do you separate each side?  I really have no idea where to go from here.  Any help would be GREATLY appreciated.\r<BR>\n" );
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document.write( "~Amanda </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #67424 by </B><A HREF=/tutors/aboutme.mpl?userid=psbhowmick><B>psbhowmick(878)</B></A><img src=\"/images/stars/stars-11.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=psbhowmick><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=psbhowmick><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=67424\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> |x+1| => |x-3|\r<BR>\n" );
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document.write( "Let us consider different cases with different sets of values of 'x':<BR>\n" );
document.write( "1. x <= -1; then the inequality becomes: -(x+1) => -(x-3) i.e. -3 >= 1 which is absurd<BR>\n" );
document.write( "2. -1<= x <= 3; then the inequality becomes: x+1 => -(x-3) i.e. x >= 1<BR>\n" );
document.write( "3. 3<= x; then the inequality becomes: x+1 => x-3 i.e. 1 >= -3 which is true\r<BR>\n" );
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document.write( "So, the solution is: x >= 1. </SPAN>\n" );
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