document.write( "Question 1059126: In order to estimate the average daily down time, a manufacturer randomly sampled 41 days of production records and found a mean of 51.75 minutes and standard deviation of 7.9 minutes. A 90% confidence interval for the population mean is
\n" );
document.write( "a. 83.21
\n" );
document.write( "b. 84.32
\n" );
document.write( "c. 85.57
\n" );
document.write( "d. 81.93
\n" );
document.write( " \n" );
document.write( "
Algebra.Com's Answer #674202 by Boreal(15235)![]() ![]() You can put this solution on YOUR website! The interval width is t(df=40,0.95)*7.9/sqrt(41); t-value will be 1.684 \n" ); document.write( "interval is 1.684*7.9/sqrt (41)=2.078 \n" ); document.write( "The CI is (49.67,53.83) \n" ); document.write( "None of the choices is a confidence interval; they are only single numbers, and none can be either part of the interval. \n" ); document.write( " \n" ); document.write( " |